Answer:
the common difference of the sequence is [tex](\frac{1}{16})[/tex]
Step-by-step explanation:
A sequence of numbers is said to be in arithmetic progression of each term of the sequence has same common difference.
Now, here first term a1 = 1/4
Second term a2 = 5/16
Third term a3 = 3/8
Now, Common difference (d) = a2 - a1 = a3 - a2
Now, a2 - a1 = [tex]\frac{5}{16} - \frac{1}{4} = \frac{5 - 4}{16} = \frac{1}{16}[/tex]
Now, a3 - a2 = [tex]\frac{3}{8} - \frac{5}{16} = \frac{6 - 5}{16} = \frac{1}{16}[/tex]
Hence, the common difference of the sequence is [tex](\frac{1}{16})[/tex]
