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PLEASE ANSWER ASAP! YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER!!! THANKS!!!!

PLEASE ANSWER ASAP YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER THANKS class=

Respuesta :

caylus
Hello,

Using vectors and scalar product:

[tex][(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0 [/tex]
Thus
[tex]\dfrac{b^2}{(a+c)(a-c)}=1 [/tex]

By the way how can we make text larger in latex \larger{.....} don't work.

Answer A




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