Answer:
The velocity at the top will be 26.4522 m/sec
Explanation:
We have given
The diameter of the loop d = 48.01 m
Radius of the loop [tex]r=\frac{d}{2}=\frac{51}{2}=25.5m[/tex]
The apparent weight at the top is given by [tex]\frac{mv^2}{r}-mg[/tex]
As the in question it is given that apparent weight is equal to 1.80 times of the real weight
[tex]\frac{mv^2}{r}-mg=1.8mg[/tex]
[tex]\frac{mv^2}{r}=2.8mg[/tex]
[tex]v=\sqrt{2.8rg}=\sqrt{2.8\times 25.5\times 9.8}=26.4522m/sec[/tex]
So the velocity at the top will be 26.4522 m/sec
