According to the quantum-mechanical model for the hydrogen atom, which of the following electron transitions would produce light with the longer wavelength: 2p→1s or 3p→1s?

Respuesta :

Answer:

[tex]2p\rightarrow 1s[/tex]

Explanation:

The energy of transition of [tex]3p\rightarrow 1s[/tex] is greater as compared to [tex]2p\rightarrow 1s[/tex] as there are more quantum levels which leads to more energy.

Also, considering the expression as:

[tex]E=\frac {h\times c}{\lambda}[/tex]

Where,  

h is Plank's constant having value [tex]6.626\times 10^{-34}\ Js[/tex]

c is the speed of light having value [tex]3\times 10^8\ m/s[/tex]

[tex]\lambda[/tex] is the wavelength

Wavelength is inversely proportional to Energy. Thus, the transition which has lower energy corresponds to higher wavelength.

Thus, answer - [tex]2p\rightarrow 1s[/tex]