Answer:
θ = 45º
Explanation:
To find the solution, let's use the projectile launch equation
R = vo² sin 2θ / g
Where vo is the initial speed of the dolphin, T is the angle of the jump and g the gravity acceleration.
To obtain a maximum range, the sine T function must be 1,
sin 2θ = 1
2θ = sin⁻¹ 1
2θ = 90
θ = 45º
Therefore, the dolphin should jump at an angle of 45º from the horizontal
