Respuesta :
Answer:
root mean square velocity of nitrogen at 25°c is 515 m/s
correct option is b) 515 m/s
Explanation:
given data
temperature = 25°c = 25 + 273 = 298 K
to find out
root mean square velocity of nitrogen molecules
solution
we know that root mean square velocity of gas is Vrms = [tex]\sqrt{\frac{3RT}{M}}[/tex] .......................1
mass of gas = M
universal gas constant = R
temperature = T
and we know mass of nitrogen = 28 g = 28 × [tex]10^{-3}[/tex] kg
Vrms = [tex]\sqrt{\frac{3RT}{M}}[/tex]
Vrms = [tex]\sqrt{\frac{3(8.314)298}{28*10^{-3}}}[/tex]
Vrms = 515.22 m/s
root mean square velocity of nitrogen at 25°c is 515 m/s
correct option is b) 515 m/s
