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Answer: hope this helps...

Step-by-step explanation:To find the x-intercept, substitute in 00 for and solve for xx. To find the y-intercept, substitute in 00 for xx and solve intercept: (1,0)(1+√52,0),(1−√52,0)(1,0),(1+52,0),(1-52,0)y-intercept: (0,1)

The value of the function when x = 3 is 41

Given the function, [tex]f(x)=x^3 + 2x^2-x-1[/tex], in order to get f(3), we need to substitute the value of x into the function as shown:

[tex]f(x)=x^3 + 2x^2-x-1\\f(3)=3^3 + 2(3)^2-3-1\\f(3)=27+2(9)-4\\f(3)=27 + 18 -4\\f(3)=27 + 14\\f(3)=41[/tex]

Hence the value of the function when x = 3 is 41

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