Answer:
[tex]3 + \dfrac{2}{log_{10}2}[/tex]
Step-by-step explanation:
given,
log₂ (800)
using logarithmic identity
logₐ a = 1
logₐ x³ = 3 logₐ x
log (ab) = log a + log b
logₐ x = [tex]\dfrac{1}{log_x a}[/tex]
now,
log₂ (800)
log₂ (2³ × 100 )
log₂ (2³) + log₂ (100)
3 log₂ (2) + log₂ (10²)
3 + 2 log₂ (10)
[tex]3 + \dfrac{2}{log_{10}2}[/tex]
