Describe the discontinuity for the function f(x)= (x^2 + 9)/(x-3)
a. There is a removable discontinuity at x=3
B. There is a hole at x= -9
C. There is a vertical asymptote
D. There is no discontinuity at x =3

I need the work to be shown so that I understand how you did.

Answer: Start by factoring the numerator and denominator of the function. A point of discontinuity occurs when a number is both a zero of the numerator and denominator. Since is a zero for both the numerator and denominator, there is a point of discontinuity there. To find the value, plug in into the final simplified equation. Hope this helps.. :D

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Describe the discontinuity for the function f(x)= (x^2 + 9)/(x-3) a. There is a removable discontinuity at x=3 B. There is a hole at x= -9 C. There is a vertical asymptote D. There is no discontinuity at x =3 I need the work to be shown so that I understand how you did.

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Describe the discontinuity for the function f(x)= (x^2 + 9)/(x-3)
a. There is a removable discontinuity at x=3
B. There is a hole at x= -9
C. There is a vertical asymptote
D. There is no discontinuity at x =3

I need the work to be shown so that I understand how you did.