Answer:
[tex]y_1=1.17\\\\y_2=-2.84[/tex]
Step-by-step explanation:
Given the following quadratic equation:
[tex]3y^2 +5y-10=0[/tex]
You need to use the Quadratic formula to find the solutions.
The Quadratic formula is:
[tex]y=\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex]
In this case you can identify that:
[tex]a=3\\b=5\\c=-10[/tex]
The, substituting this values into the Quadratic formula, you get the following solutions for the given quadratic equation:
[tex]y=\frac{-5\±\sqrt{5^2-4(3)(-10)} }{2(3)}\\\\\\y_1=1.17\\\\y_2=-2.84[/tex]
