Answer:
v_x = -6.00 m/s
v_y = 10.4 m/s
Explanation:
To calculate the velocity of the x-component we must use the cosine function:
[tex]v_{x} =-v_{0}cos(\alpha )[/tex], where ∝ is the angle 60°, and [tex]v_{0}[/tex] is the velocity 12.0 m/s (note: the negative sign due to the question stating it is "above the negative x-axis).
This gives us a value [tex]v_{x} =-6[/tex] m/s
Similarly for the y-component, we must use the sine function:
[tex]v_{y}=v_{0}sin(\alpha)[/tex]
which gives us a value [tex]v_{y} = 10.392...[/tex] ≈ 10.4 m/s (since there are 3 significant figures in the information given in the question, this is rounded to 10.4 m/s).
