Answer:
The roots of equation are real and distinct.
Step-by-step explanation:
Given that
ax²+bx+c=0
a+c=0
To find the behavior of roots we have to find out D
[tex]D=\sqrt{b^2-4ac}[/tex]
If
D> 0 Two real distinct roots
D=0 Two equal roots
D<0 Tow imaginary roots
[tex]D=\sqrt{b^2-4ac}[/tex]
a+c=0
a= - c
[tex]D=\sqrt{b^2-4\times (-c)\times c}[/tex]
[tex]D=\sqrt{b^2+4\times c^2}[/tex]
It means that D>0 .So the roots of equation is real and distinct.
