Answer:
Solved (x-3/4)(x+1/4)
Step-by-step explanation:
16x²-8x-3=0
we can find the factors of the above quadratic equation using shridharacharya formula which given as
[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
a= 16, b= -8 and c= -3 putting these values in above equation we can find the factors of x as
[tex]x=\frac{8\pm \sqrt{8^2-4\times16\times(-3)} }{2\times16}[/tex]
x= 3/4 and -1/4
now 16x²-8x-3 can also be written as (x-3/4)(x+1/4) as 3/4 and 1/4 are the roots of the equation.
on solving expression is equivalent to the original: 16x²-8x-3 we will again obtain 16x²-8x-3. Hence it is varified that the factored expression is equivalent to the original: 16x²-8x-3
