Respuesta :
First of all, you have to manipulate the equation into the standard
[tex]ax^2+bx+c=0[/tex]
form. You can simplify the 1's on both sides and you have
[tex]3x^2-2x=0[/tex]
This means that your coefficients are
[tex]a=3,\quad b=-2,\quad c=0[/tex]
And since the solving formula is
[tex]x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Plugging your values yields
[tex]x_{1,2}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4\cdot 3\cdot 0}}{2\cdot 3}[/tex]
The correct substitution of the values a, b, and c into the quadratic formula is [tex]x = \frac{-(-2)\; \pm \;\sqrt{(-2)^2\; - \;4(3)(0)}}{2(3)}\\[/tex]
Given the following equation:
- [tex]1 = -2x + 3x^2 + 1[/tex]
To show the correct substitution of the values a, b, and c into the quadratic formula:
What is a quadratic equation?
A quadratic equation is a mathematical expression in which one (1) of its variables is to the degree (power) of 2 and as such has two roots.
In Mathematics, the standard form of a quadratic equation is given by;
[tex]ax^2 +bx+c=0[/tex]
Thus, we would express the given equation in standard quadratic form as follows:
[tex]1 = -2x + 3x^2 + 1\\ \\ 3x^2 + 1-2x-1=0\\ \\ 3x^2-2x=0[/tex]
Where:
- a = 3
- b = -2
- c = 0
For the quadratic formula:
Mathematically, the quadratic formula is given by:
[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a} [/tex]
Substituting the parameters into the formula, we have;
[tex]x = \frac{-(-2)\; \pm \;\sqrt{(-2)^2\; - \;4(3)(0)}}{2(3)}\\ [/tex]
Read more on quadratic equation here: https://brainly.com/question/1214333