Answer:
Diameter of pile of sand is 7.57 feet.
Step-by-step explanation:
The volume of the cone = [tex]\frac{1}{3} (\pi ) r^{2} h[/tex]
Here, let π = 3.14,H = 10 ft, and V = 150 cubic feet.
So, putting the values in the formula, we get
[tex]150 = \frac{1}{3} \times 3.14 \times r^{2} \times 10[/tex]
or , [tex]r^{2} = \frac{150 \times 3 }{3.14 \times 10}[/tex]
or, [tex]r^{2}[/tex] = 14.33
or, r = [tex]\sqrt{14.33}[/tex]
⇒ r = 3.78 ft
As we know, 2 x RADIUS = DIAMETER
So, diameter of pile of sand = 2x 3.78= 7.57 feet.
