Respuesta :
Answer:
The answer to your question is:
Explanation:
Compound Cation Anion Number of electrons
LiCl Li⁺¹ Cl⁻¹ one
NaF Na⁺¹ F⁻¹ one
CaO Ca⁺² O⁻² two
BaS Ba⁺² S⁻² two
NaBr Na⁺¹ Br⁻¹ one
Answer:
Explanation:
To understand how the answer is gotten, it is recommended to prepare the ionic equation for watch of the compounds and this can be gotten by considering the valency of the atoms.
LiCl;
Li belongs to group 1 so it has a valency of + 1
Cl belongs to group 7 so it has a valency of -1
Ionic equation is given as; Li+ + Cl- -> LiCl
The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.
NaF;
Na belongs to group 1 so it has a valency of + 1
F belongs to group 7 so it has a valency of -1
Ionic equation is given as; Na+ + F- -> NaF
The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.
CaO;
Ca belongs to group 1 so it has a valency of + 2
Cl belongs to group 6 so it has a valency of -2
Ionic equation is given as; Ca2+ + O2- -> CaO
The number of electrons that are transferred between the cation and anion to form the ionic bond is 2.
BaS;
Ba belongs to group 2 so it has a valency of +2
S belongs to group 6 so it has a valency of -2
Ionic equation is given as; Ba2+ + S2- -> BaS
The number of electrons that are transferred between the cation and anion to form the ionic bond is 2.
NaBr;
Na belongs to group 1 so it has a valency of + 1
Br belongs to group 7 so it has a valency of -1
Ionic equation is given as; Na+ + Br- -> NaBr
The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.