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Write the equation 8y = 1/12x – 0.8 in standard form. Identify A, B, and C.

A. 480x + 5y = –48 where A = 480, B = 5, and C = -48


B. 480x – 1y = –48 where A = 480, B = –5, and C = -48


C. 5x – 480y = 48 where A = 5, B = –480, and C = 48


D. 1x + 96y = 9.6 where A = 1, B = –96, and C = 0.8

Respuesta :

mberisso

Answer:

Naswer C: [tex]5x-480y=48[/tex]

Step-by-step explanation:

Let's first write all the coefficients in fraction form, noticing that 0.8 is the same as [tex]\frac{8}{10} =\frac{4}{5}[/tex], and then group the term in x and the term in y on one side of the equal sign, moving the pure numerical coefficient to the other side:

[tex]8y=\frac{1}{12} x-\frac{4}{5} \\0=\frac{1}{12} x-8y-\frac{4}{5}\\\frac{4}{5} =\frac{1}{12} x-8y[/tex]

Now find the LCD for the existing denominators (5 and 12). This is: LCD = 60

Use the LCD we just found, to multiply both sides of the equation, so as to get rid of all denominators in the equation:

[tex]\frac{4}{5} =\frac{1}{12} x-8y\\60*\frac{4}{5} =60*(\frac{1}{12} x-8y)\\12*4=\frac{60}{12} x-60*8y\\48=5x-480y\\5x-480y=48[/tex]

notice that our equality matches answer C provided.

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