Respuesta :
Answer:
θ = 19.47°
Explanation:
given,
mass of the barge = 1000 kg
force applied to pull = 80 N
direction = 30° west to north
force exerted by the cable = 120 N
direction = ?
first cable is pulling
in north direction = 80 cos ∅
               = 80 cos 30°
               = 69.28 N
in west direction = 80 sin ∅
               = 80 sin 30°
               = 40 N
the other cable will pull in the opposite direction of west
now,
[tex]120 sin \theta = 40[/tex]
[tex]sin \theta = \dfrac{40}{120}[/tex]
[tex]\theta = sin^{-1}{\dfrac{1}{3}}[/tex]
θ = 19.47°
the direction of the cable will be equal to θ = 19.47°
