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A researcher records the following time spent sleeping per night (in hours) in a group of participants: 5.8 ± 1.8 (M ± SD). The researcher decides to categorize participants who sleep between 6 and 8 hr as moderate sleepers. What percentage of participants fell in this category?

Respuesta :

Answer:  40.68 %

Step-by-step explanation:

We need  to find the interval between the values 0.2 and 2.2

 0.2 ≤ z ≤ 2.2  

Since in the standardized normal curve the mean 5.8 will be 0

Area for z values ≥ 0.2        ⇒    0.0793  and  area for z ≤ 2.2

area between 0 and 0.2 is 0.0793 ;  and area between 0 to 2.2  is 0.4861

this last value includes the previous value at the left of  z = 0.2

As we are looking for participants in the interval   0.2 ≤ z ≤ 2.2 we need to subtract  areas 0.4861 - 0.0793 = 0.4068 express in % is 40.68 %

     

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