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Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s and was brought jarringly back to rest in only 1.40 s. Calculate his stopping acceleration in multiples of g.

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Answer:

a = 20.532 g

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-282}{1.4}\\\Rightarrow a=-201.42\ m/s^2[/tex]

Magnitude of deceleration is 201.42 m/s²

g = 9.81 m/s²

Dividing a by g

[tex]\frac{a}{g}=\frac{201.42}{9.81}\\\Rightarrow \frac{a}{g}=20.532\\\Rightarrow a=20.532g[/tex]

a = 20.532 g

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