Answer:
The nearest value is 1811 km
Explanation:
This is an exercise in kinematics, with uniform movement
   v = x / t
Let's reduce time to seconds
  t1 = 2 h (3600s / 1h) = 7200 s
  t2 = 15 min (60s / 1min) = 900 s
The total time is
   t = t1 + t2
   t = 7200 +900
   t = 8100 s
We calculate the distance
   x = v t
We reduce speed to mile / h to km / s
  v = 500 mile / h (1,609 km / 1 mills) (1h / 3600s)
  v = 0.2235 km / s
 Â
  x = 0.2235 8100
  x = 1810.5 km
The nearest value is 1811 km