Answer:
[tex]\Delta K = 52J[/tex]
Explanation:
The change in kinetic energy will be simply the difference between the final and initial kinetic energies: [tex]\Delta K=K_f-K_i[/tex]
We know that the formula for the kinetic energy for an object is:
[tex]K=\frac{mv^2}{2}[/tex]
where m is the mass of the object and v its velocity.
For our case then we have:
[tex]\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}[/tex]
Which for our values is:
[tex]\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J[/tex]
