Answer:
x= (-1+ √17) or (-1-√17)
Step-by-step explanation:
In this question, we have to solve for x from the given equation x² +2x+1 =17
Now, the equation can be rearranged to x² +2x -16 =0.
Here we can not apply the process of factorization to get the value of x.
Hence, we will use the Shridhar Acharya formula to solve the value of x.
{This formula gives, if ax² +bx +c =0 then, the value of x can be solved as
x=[-b±√(b²-4ac)]/2a }
Hence, in this case, the solution for x will be
x=[tex]\frac{-2+\sqrt{2^{2}-4(1)(-16) } }{2(1)} or \frac{-2-\sqrt{2^{2}-4(1)(-16) } }{2(1)}[/tex]
⇒ x=[tex]\frac{-2+2\sqrt{17} }{2} or \frac{-2-2\sqrt{17} }{2}[/tex]
⇒ x= (-1+ √17) or (-1-√17) (Answer)
