Answer with Step-by-step explanation:
We are given that two events A and B are mutually exclusive.
[tex]A\cap B=\phi[/tex]
[tex]P(A\cap B)=0[/tex]
[tex]P(A)\neq 0[/tex]
[tex]P(B)\neq 0[/tex]
a.For mutually exclusive events,
[tex]P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{P(A)}=0[/tex]
Therefore, event A can not occurred if event B has occurred because two events can not occur together.
Answer:No, by definition mutually exclusive events cannot occur together.
b.When two events are independent
Then , [tex]P(A\cap B)=P(A)\cdot P(B)[/tex]
[tex]P(A/B)=\frac{P(A)\cdot P(B)}{P(B)}=P(A)[/tex]
If two events are mutually exclusive then
[tex]P(A\cap B)=0[/tex]
Then , [tex]P(A/B)=0[/tex]
Therefore, [tex]P(A/B)\neq P(A)[/tex]
Hence, we can concluded that events A and B are not independent if they are mutually exclusive.
Answer:Yes, [tex]P(A/B)\neq P(A)[/tex]