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The rate of a reaction is directly proportional to the square of the concentration of A and inversely proportional to concentration of B. If B increases by 100%, which of the following is closest to the % change in concentration of A required to keep the rate unchanged?

Respuesta :

Answer:

Step-by-step explanation:

Given that the rate of a reaction is directly proportional to the square of the concentration of A and inversely proportional to concentration of B.

i.e. R = rate of a reaction = [tex]\frac{kA^2}{B}[/tex]

where A shows the concentration of A and B that of B.

If B increases by 100%, then we have B to be replaced by 2B

But R is the same

i.e. [tex]\frac{kA^2}{B}=\frac{kA_1^2}{2B}[/tex] where new A= A1

Simplify to get

[tex]2A^2 = A_1^2\\A_1=\sqrt{2}  A[/tex]

So A increases to sqrt of 2 times original concentration.

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