Answer:
do{
std::cout << "input an even number: ";
std::cin >> n;
even=n%2;
if (even==0)
std::cout << "Good job!\n";
else
std::cout << n <<" is not an even number\n";
}while(n!=999);
Explanation:
#include <iostream>
#include <string>
int main()
{ int n=0,even;
do{
std::cout << "input an even number: "; //print on screen to input the number
std::cin >> n; //put that value on n variable
even=n%2;
if (even==0) //if even is zero the number is even
std::cout << "Good job!\n";
else //if even is not zero the number is odd
std::cout << n <<" is not an even number\n";
}while(n!=999); // we will repeat the proccess while n is diffrente from 999
}
Answer:
int value;
while(1){
scanf("%d\n", &value);
if(value == 999)
break;
if(value%2 == 0)
printf("Good job");
else if(value%2 == 1)
printf("%d is not an even number", value);
}
Explanation:
I am going to write a C code for this.
The while(1) runs until the break command. So
int value;
while(1){
scanf("%d\n", &value);
if(value == 999)
break;
if(value%2 == 0)
printf("Good job");
else if(value%2 == 1)
printf("%d is not an even number", value);
}
