Answer:
At 6% was loaned $14,000
Step-by-step explanation:
Let
x -----> amount loaned at 6%
($20,000-x) ----> amount loaned at 11%
we know that
The interest received on the amount loaned at 6% plus the interest received on the amount loaned at 11% must equal $1,500.
Remember that
[tex]6\%=6/100=0.06[/tex]
[tex]11\%=11/100=0.11[/tex]
so
[tex]0.06(x)+0.11(20,000-x)=1,500[/tex]
[tex]0.06x+2,200-0.11x=1,500[/tex]
[tex]0.11x-0.06x=2,200-1,500[/tex]
[tex]0.05x=700[/tex]
[tex]x=\$14,000[/tex]
therefore
At 6% was loaned $14,000