Answer:
B.[tex]n=5, l=2,m_l=0,m_s=+\frac{1}{2}[/tex]
Step-by-step explanation:
We are given that an electron in a 5d orbital
We have to find the set of quantum numbers correctly describes an electron in a 5d orbital.
We know that
n=Principle quantum number
Therefore, n=5
Angular momentum quantum number =l=0,1,2,3,..(n-1)
l=0 =s-orbital
l=1=p- orbital
l=2=d=orbital
l=3=f orbital
Therefore, l=2
Magnetic quantum number=[tex]m_l=-l,..,0,..l[/tex]
[tex]m_l=-2,-1,0,1,2[/tex]
5d orbital have only one electron Magnetic quantum number have no fixed values
Therefore,we can take [tex]m_l=0[/tex]
Spin quantum number[tex]m_s=\pm\frac{1}{2}[/tex]
5d orbital have only one electron .Then, it has spin-up
Therefore, [tex]m_s=+\frac{1}{2}[/tex]
Answer:B.[tex]n=5, l=2,m_l=0,m_s=+\frac{1}{2}[/tex]
