Respuesta :
Answer:
Part 1) The equation is [tex]y=1.92x+8.76[/tex]
Part 2) The value of the card in 2006 Â was [tex]\$27.96[/tex]
Step-by-step explanation:
Part 1) Express the relationship relating the value of the card y in dollars and the number of years x the player has been in retirement with an equation
Let
x -----> the number of years since 1996
y ----> the value of the card
we know that
The linear equation in slope intercept form is
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-coordinate of the y-intercept
In this problem
we have that
1) The value of the card has increased by ​$ 1.92 each year since 1996
so
The unit rate or slope of the linear equation is [tex]m=1.92\frac{\$}{year}[/tex]
2) When he retired in 1996 his card was worth ​$ 8.76
Remember that the y-intercept is the value of y when the value of x is equal to zero
In this problem, the y-intercept is the value of the card when the year is 1996 (the number of years is zero)
so
The y-intercept is the point (0,8.76)
[tex]b=\$8.76[/tex]
substitute the values in the linear equation
[tex]y=1.92x+8.76[/tex]
This relation is not proportional, because the linear equation not passes trough the origin
Part 2) What was the value of the card in 2006​?
Determine the number of years since 1996
x=2006-1996=10 years
substitute the value of x in the equation and solve for y
[tex]y=1.92(10)+8.76[/tex]
[tex]y=\$27.96[/tex]