Answer:
V= 2.82 m/s
Explanation:
Given that
μs = 0.4
Lets take track is circular with radius 2 m.
Condition before just start to slip
[tex]\dfrac{mV^2}{r}=\mu _smg[/tex]
[tex]\dfrac{V^2}{r}=\mu _sg[/tex]
[tex]V^2=\mu rg[/tex]
[tex]V=\sqrt{\mu rg}\ m/s[/tex]
Now by putting the values
Lets take r = 2 m
μs = 0.4
[tex]V=\sqrt{0.4\times 2\times 9.81}\ m/s[/tex]
V= 2.82 m/s