Answer:
The magnitude of the horizontal displacement of the rock is 7.39 m/s.
Explanation:
Given that,
Initial speed = 11.5 m/s
Angle = 50.0
Height = 30.0 m
We need to calculate the horizontal displacement of the rock
Using formula of horizontal component
[tex]v_{x}=u\cos\theta[/tex]
Put the value into the formula
[tex]v_{x}=11.5\times\cos50[/tex]
[tex]v_{x}=7.39\ m/s[/tex]
Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.
