If the scale factor of Figure A to Figure B is 7:2 find the perimeter of Figure A.

Answer:
Step-by-step explanation:
The proportion would be between the permiters and the given ratio:
[tex]\frac{7}{2}=\frac{P}{p}[/tex]
Where [tex]P[/tex] is the perimeter of the bigger figure and [tex]p[/tex] is the perimeter of the smaller figure.
Remember that the perimeter is the sum of all sides, using all given values and solving for [tex]P[/tex], we have
[tex]\frac{7}{2}=\frac{P}{9+5+9+12}\\\frac{7}{2}=\frac{P}{35}\\ \frac{7(35)}{2}=P\\ P=\frac{245}{2}=122.5[/tex]
Therefore, the permiter of Figure A is 122.5 units.
The perimeter is the sum of all sides of the given shape, so according to the scale factor, the perimeter of the Figure A is 122.50 units.
Given information:
The scale factor of fig. A to fig. B is 7:2
As, the proportion would be between the perimeters
So,
[tex]\frac{P_A}{P_B} =\frac{7}{2}[/tex]
Now, we know that the perimeter is the sum of all sides of the given shape
Hence taking the values from the given figure and putting in the above expression
we get,
[tex]\frac{P_A}{9+5+9+12} =\frac{7}{2} \\\\P_A=(7\times 35)/2\\P_A=2456/2\\P_A=122.50 \;\text {units}[/tex]
Hence, the perimeter of the Figure A is 122.50 units.
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