The airplane went 5195.33 km
Step-by-step explanation:
Distance = speed × time
The given is:
1. An airplane flies for 3.5 hours with a constant speed of 840 km/h
2. Then for another 3 hours 19 minutes with a constant speed of
680 km/h
We need the distance it traveled
For the first part
∵ The time is 3.5 hours
∵ The speed is 840 km/h
∵ Distance = speed × time
- Substitute the values of the speed and the time in the rule
∴ Distance = 840 × 3.5
∴ Distance = 2940 km
For the second part
∵ The time is 3 hours and 19 minutes
- We must change the minutes to hour
∵ 1 hour = 60 minutes
∴ 19 minutes = [tex]\frac{19}{60}[/tex] hour
∴ The time is [tex]3\frac{19}{60}[/tex] hour
∵ The speed is 680 km/h
∴ Distance = 680 × [tex]3\frac{19}{60}[/tex]
∴ Distance = [tex]2255\frac{1}{3}[/tex] km
∴ The total distance = 2940 + [tex]2255\frac{1}{3}[/tex]
∴ The total distance = [tex]5195\frac{1}{3}[/tex] km
It went 5195.33 km
Learn more:
You can learn more about constant speed in brainly.com/question/568302
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