Answer:
0.042 kg m/s
Explanation:
In order to solve this, we need to find the final velocity of the block at the moment it its the ground.
The motion of the block is a free fall motion, so it is a uniform accelerated motion, so we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where:
v is the final velocity
u = 0 is the initial velocity (it starts from rest)
[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity (we chose downward as positive direction)
s = 22.13 m is the displacement
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(22.13)}=20.8 m/s[/tex]
Now we can find the final momentum of the block, using the equation:
p = mv
where
m = 2.0 g = 0.002 kg is the mass of the block
Substituting,
[tex]p=(0.002)(20.8)=0.042 kg m/s[/tex]
