The time it takes an object to fall from a great height depends on the object's acceleration due
to gravity, as well as the height from which the object is dropped. The formula h=1/2gt^2 can
be used to describe this relationship, with t representing time (in seconds), h representing the
height of the object (in feet), and g representing the object's acceleration due to gravity, which is
32 ft/s on Earth. If a cliff diver leaps into the water from a height of 164 feet, how long will it
ake him to reach the water? Assume that air resistance is negligible and does not have an effect. ​

Respuesta :

It will take him 3.20 seconds to reach the water

Step-by-step explanation:

The given is;

1. The formula h = [tex]\frac{1}{2}[/tex] g t² can  be used to describe the

   relationship, with t representing time (in seconds), h representing

   the  height of the object (in feet), and g representing the object's

   acceleration due to gravity

2. The acceleration of gravity is 32 ft/s²

3. A cliff diver leaps into the water from a height of 164 feet

4. The air resistance is negligible and does not have an effect

We need to find how long will it take him to reach the water

∵ h = [tex]\frac{1}{2}[/tex] g t²

∵ h = 164 feet

∵ g = 32 ft/s²

- Substitute these values in the formula above

∴ 164 = [tex]\frac{1}{2}[/tex] (32) t²

∴ 164 = 16 t²

- Divide both sides by 16

∴ 10.25 = t²

- Take √ for both sides

∴ t = 3.20 seconds

It will take him 3.20 seconds to reach the water

Learn more:

You can learn more about speed, time and distance in brainly.com/question/13053630

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