A study reports that 36​% of companies in Country A have three or more female board directors. Suppose you select a random sample of 100 respondents. Complete parts​ (a) through​ (c) below. a. What is the probability that the sample will have between 29​% and 38​% of companies in Country A that have three or more female board​ directors? The probability is . 36. ​(Round to four decimal place

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Answer:

The probability is 0.6440

Step-by-step explanation:

The probability that x companies from the 100 in Country A have 3 or more female board directors follows a binomial distribution, so it is calculated as:

[tex]P(x)=100Cx*0.36^{x}*(1-0.36)^{100-x}[/tex]

Where 100 is the number of respondent and 0.36 is the probability that a company in country A have three or more female directors.

Additionally, 100Cx is calculated as:

[tex]100Cx=\frac{100!}{x!(100-x)!}[/tex]

Then, said that the sample will have between 29​% and 38​% of companies with three or more female board​ directors is equivalent to said that the sample will have between 29 and 38 companies with three or more female board​ directors.

So, the probability that the sample will have between 29​% and 38​% of companies in Country A that have three or more female board​ directors is calculated as:

P(29≤x≤38) = P(29) + P(30) + P(31) + ... + P(37) + P(38)

Where, for example, P(29) is:

[tex]P(29)=100C29*0.36^{29}*(1-0.36)^{100-29}=0.0292[/tex]

Finally, P(29≤x≤38) is equal to:

P(29≤x≤38) = 0.6440