a restaurant has a 50 gallon fish tank, the water in the tank evaporates at a rate of -2.5 a week, but the owner adds 3 gallons of water to the tank every 10 days , after the owner added 3 gallons today there were 44 gallons of water in the tank , how much water will be in the tank when the owner adds 3 gallons 70 days from today

Respuesta :

The water in the tank 70 days from today will be 42 gallons.

Step-by-step explanation:

Current water in the tank is 44 gallons

As per my understanding, water evaporates at -2.5 gallons a week

Owner adds 3 gallons of water every 10 days

To find water in the tank after 70 days,

1. Find the number of weeks in 70 days

a) 1 month = 30 days

x months = 70 days

Cross multiply

30x = 70

x = [tex]\frac{70}{30}[/tex]

x = 2.3 months

b) 1 month = 4 weeks

2.3 months = y weeks

y = 2.3 x 4

y = 9.2 weeks

c) Each week, 2.5 gallon evaporates

1 week = 2.5 gallon

9.2 weeks = z gallons

z = 9.2 x 2.5

z = 23 gallons

2. After every 10 days, 3 gallons are added.

In 70 days, 3 gallons are added 7 times so,

3 x 7 = 21 gallons

3. Water in the tank 70 days from today = Water in tank + water added - water evaporated

Water in the tank 70 days from today = 44 + 21 - 23 = 42 gallons

Therefore, the water in the tank 70 days from today will be 42 gallons.

Keywords: Equations, gallons

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