For this case we have that Lauren's initial amount of money was $ 50, if he spends $10 and $12 on admission and strawberry pie respectively we have:
$50 - ($10 + $12) = $50- $22 = $28
That is, she has $ 28 left
n: Let the variable that represents the amount of games Lauren can play.
Then, it must be fulfilled that:
[tex]0.75n \leq28\\n \leq \frac {28} {0.75}\\n \leq37.33[/tex]
Thus, Lauren can play 37 times the game (at most)
ANswer:
[tex]n \leq37.33[/tex]
Thus, Lauren can play 37 times the game (at most)