Answer:
Mason has
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
Total amount:
Hence,
[tex]49(56-x)+20x+3(x+9)=2,355\\ \\2,744-49x+20x+3x+27=2,355\\ \\-49x+3x+20x=2,355-2,744-27\\ \\-26x=-416\\ \\26x=416\\ \\x=16[/tex]
Mason has