Determine a forma irredutível da razão entre cada par de medidas apresentada na ordem dada: a) 64.000 kg e 2 t b)5 l e 25 l c)4cm e 1 m d)2 m³ e 8 m ³

Respuesta :

Answers:

a) [tex]32[/tex]

b) [tex]\frac{1}{5}[/tex]

c) [tex]0.04[/tex]

d) [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

The question in english is written below:

Determine the irreducible form of the ratio between each pair of measurements given in the following order: a) 64,000 kg and 2 Tm b) 5L and 25 L c) 4cm and 1 m d) [tex]2 m^{3}[/tex] and [tex]8 m^{3}[/tex]

a) Firstly, we have to convert the [tex]2 Tm[/tex] to [tex]kg[/tex]:

[tex]2 Tm \frac{1000 kg}{1 Tm}=2000 kg[/tex]

Now we can work with the same units:

[tex]\frac{64000 kg}{2000 kg}=32[/tex]

b) Here both quantities are in liters ([tex]L[/tex]):

[tex]\frac{5L}{25 L}=\frac{1}{5}[/tex]

c) Firstly, we have to convert the measurement from [tex]cm[/tex] to [tex]m[/tex]:

[tex]4 cm \frac{1m}{100 cm}=0.04 m[/tex]

Now we can work with the same units:

[tex]\frac{0.04 m}{1 m}=0.04[/tex]

d) Here both quantities are in cubic meters:

[tex]\frac{2 m^{3}}{8 m^{3}}=\frac{1}{4}[/tex]