Answer:
90.1 N
Explanation:
We are given that
The ropes makes an angle with horizontal=[tex]46.6^{\circ}[/tex]
Beth exerts a force on the rope=124 N
We have to magnitude of the upward component of the force on the stake.
Vertical component is always sin and horizontal component is always cos.
Therefore, the magnitude of the upward component of the force acting on the stake=[tex]124 sin 46.6^{\circ}[/tex]
The magnitude of the upward component of the force acting on the stake=[tex]124 \times 0.727[/tex]
The magnitude of the upward component of the force acting on the stake=90.148 N
Hence, the magnitude of the upward component of force acting on the stake=90.1 N
Answer:
The upward component force in magnitude is 90.095 N
Solution:
As per the question:
The angle that the rope make with the horizontal, [tex]\theta = 46.6^{\circ}[/tex]
The force exerted by Beth on the rope, F = 124 N
Now, the upward component of the force that acts on the stake is the vertical component or the cosine component of the force that Beth exerts on the rope.
The magnitude of this component of force is given by:
[tex]F_{up} = Fsin\theta [/tex]
[tex]F_{up} = 124\times sin46.6^{\circ} =90.095 N[/tex]
[tex]F_{up} = 90.095 N[/tex]
