Answer:
4.9 m/s
Explanation:
Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the ball in this problem,
u = 0 (it starts from rest)
[tex]a=4 m/s^2[/tex] is the acceleration
s = 3 m is the distance covered
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(4)(3)}=4.9 m/s[/tex]
