Answer:
-100.27 m/s
42.72 m/s
Explanation:
[tex]m_1[/tex] = Mass of first ball = 32 kg
[tex]m_2[/tex] = Mass of second ball = 70 kg
[tex]u_1[/tex] = Initial Velocity of first ball = 96 m/s
[tex]u_2[/tex] = Initial Velocity of second ball = -47 m/s
[tex]v_1[/tex] = Final Velocity of first ball
[tex]v_2[/tex] = Final Velocity of second ball
For elastic collision
[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]
[tex]v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{32-70}{32+70}\times 96+\frac{2\times 70}{32+70}\times -47\\\Rightarrow v_1=-100.27\ m/s[/tex]
Final velocity of the 32 kg ball is -100.27 m/s
[tex]v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 32}{32+70}\times 96+\frac{70-32}{32+70}\times -47\\\Rightarrow v_2=42.72\ m/s[/tex]
Final velocity of the 70 kg ball is 42.72 m/s
