For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We must graph the following equation of the line:
[tex]y = \frac {2} {3} x-2[/tex]
The line cuts at the point [tex](x, y) :( 0, -2)[/tex]
The slope is positive.
For [tex]x = 0[/tex] then [tex]y = -2[/tex]
For[tex]x = 1[/tex]then [tex]y = - \frac {4} {3}[/tex]
We locate the points on the coordinate axis and draw the line.
Answer:
See attached image
