Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The partial pressure of oxygen (PO2) in such conditions is _. Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The partial pressure of oxygen (PO2) in such conditions is _. 21/760 16 mm Hg 760/21 120/75 160 mm Hg SubmitR

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Аноним Аноним · Answer 1 · 2019-10-24T08:20:20+02:00

Answer: The partial pressure of oxygen is 160 mmHg

Explanation:

We are given:

Percent of oxygen in air = 21 %

Mole fraction of oxygen in air = [tex]\frac{21}{100}=0.21[/tex]

To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:

[tex]p_{O_2}=p_T\times \chi_{O_2}[/tex]

where,

[tex]p_{O_2}[/tex] = partial pressure of oxygen = ?

[tex]p_T[/tex] = total pressure of air = 760 mmHg

[tex]\chi_{O_2}[/tex] = mole fraction of oxygen = 0.21

Putting values in above equation, we get:

[tex]p_{O_2}=760mmHg\times 0.21\\\\p_{O_2}=160mmHg[/tex]

Hence, the partial pressure of oxygen is 160 mmHg