Respuesta :

Answer:

40th term of arithmetic sequence = 442

Step-by-step explanation:

Here arithmetic sequence is given as 13, 24, 35, ....

First term, f = 13

Common difference , d = 24 - 13 = 11

We know that n th term of AP is

                             [tex]t_n=f+(n-1)d[/tex]

We need to find 40 th term, that is n = 40

Substituting

                             [tex]t_{40}=13+(40-1)\times 11=13+39\times 11=13+429=442[/tex]

40th term of arithmetic sequence = 442