Answer: The percentage yield of water is 9.5 %
Explanation:
We are given:
Moles of hydrogen = 14 moles
Moles of oxygen = 10 moles
The chemical equation for the formation of water from hydrogen and oxygen follows:
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of hydrogen gas reacts with 1 mole of oxygen gas
So, 14 moles of hydrogen gas will react with = [tex]\frac{1}{2}\times 14=7mol[/tex] of oxygen gas
As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent
Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of hydrogen gas produces 2 moles of water
So, 14 moles of hydrogen gas will produce = [tex]\frac{1}{2}\times 14=7mol[/tex] of water
To calculate the percentage yield of water, we use the equation:
[tex]\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]
Experimental yield of water = 1.33 moles
Theoretical yield of water = 14 moles
Putting values in above equation, we get:
[tex]\%\text{ yield of water}=\frac{1.33mol}{14mol}\times 100\\\\\% \text{yield of water}=9.5\%[/tex]
Hence, the percent yield of the water is 9.5 %.
