Answer:
a) The kinetic energy of the leaf is the same for both people:
ĪK=\frac{1}{2} mv^2
b) The change in gravitational energy Ā from the point of view:
Person on the ground: ĪG= -mgh
Person on the ladder: ĪG= mgh
Explanation:
We consider point 1 when it falls off the tree and point 2 when it hits the ground.
a) Person on the ground:
Kinetic energy at point 1 is Kā=0
Kinetic energy at point 2 is Kā=[tex]\frac{1}{2} mv^2[/tex]
ĪK=[tex]\frac{1}{2} mv^2[/tex]-0
Person on the ladder:
Kinetic energy at point 1 is Kā=0
Kinetic energy at point 2 is Kā=\frac{1}{2} mv^2
ĪK=[tex]\frac{1}{2} mv^2[/tex]-0
b) Person on the ground:
Gravitational energy at point 1 is Gā=mgh
Kinetic energy at point 2 is Gā=0
ĪG=0-mgh=-mgh
Person on the ladder:
Kinetic energy at point 1 is Gā=0
Kinetic energy at point 2 is Gā=mgh
ĪG=mgh-0=mgh