Answer:
- 0.4
Step-by-step explanation:
The radius of a circle and a tangent to the circle are perpendicular to each other at the point of contact.
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{2.5}[/tex] = - 0.4
Answer:
-0.4
Step-by-step explanation:
Given
Let r = radius
r = -2.5
The relationship between the slope of the tangent of the line and the radius is as follows;
Let ∆s represent slope
Mathematically, ∆s = -1/r
Substitute 2.5 for r
∆s = -1/2.5
∆s = -0.4
Hence, given that the radius of circle is 2.5, the slope of the line tangent to is -0.4
