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A ray of light traveling in glass (refractive index na) reflects at the flat interface between the glass and water (refractive index nb). The incident ray in glass makes an angle of θa with the normal to the interface and the reflected ray makes an angle of θr with the normal. If na is increased (by using a different type of glass) but θa is kept the same, how does θr change?

Respuesta :

Answer:

θr  will increase.

Explanation:

We know that when light travel from one medium to another medium the relationship between refractive index and angle given as

na. sinθa = nb . sinθr

[tex]sin \theta _r=\dfrac{n_asin\theta _a}{n_b}[/tex]

If na is increased (by using a different type of glass) but θa is kept the same then sinθr will also increase.

So answer is θr  will increase.

mickymike92

Based on the relationship between refractive index and angle, angle of refraction, θr will increase

What us refractive index?

Refractive index of a medium is the ratio of sine of the angle of incidence of light and the angle of refraction through the medium.

  • Refractive index, n = sinθi/sinθr

.

When light travels between two media, the relationship between refractive index and angle given as follows:

  • na × sinθa = nb × sinθr

Then;

  • sinθr = na × sinθa / nb

If na is increased but θa is kept the same then sinθr will also increase.

Therefore, angle of refraction, θr  will increase.

Learn more about angle of refraction at: https://brainly.com/question/16050768